Chapter 5 Conditionals and recursion
5.1 Modulus operator
The modulus operator works on integers and yields the remainder
when the first operand is divided by the second. In Python, the
modulus operator is a percent sign (
>>> quotient = 7 / 3 >>> print quotient 2 >>> remainder = 7 % 3 >>> print remainder 1
So 7 divided by 3 is 2 with 1 left over.
Also, you can extract the right-most digit or digits from a number. For example, x % 10 yields the right-most digit of x (in base 10). Similarly x % 100 yields the last two digits.
5.2 Boolean expressions
A boolean expression is an expression that is either true or false. The following examples use the operator ==, which compares two operands and produces True if they are equal and False otherwise:
>>> 5 == 5 True >>> 5 == 6 False
>>> type(True) <type 'bool'> >>> type(False) <type 'bool'>
The == operator is one of the relational operators; the others are:
x != y # x is not equal to y x > y # x is greater than y x < y # x is less than y x >= y # x is greater than or equal to y x <= y # x is less than or equal to y
Although these operations are probably familiar to you, the Python symbols are different from the mathematical symbols. A common error is to use a single equal sign (=) instead of a double equal sign (==). Remember that = is an assignment operator and == is a relational operator. There is no such thing as =< or =>.
5.3 Logical operators
There are three logical operators: and, or, and not. The semantics (meaning) of these operators is similar to their meaning in English. For example, x > 0 and x < 10 is true only if x is greater than 0 and less than 10.
n%2 == 0 or n%3 == 0 is true if either of the conditions is true, that is, if the number is divisible by 2 or 3.
Finally, the not operator negates a boolean expression, so not (x > y) is true if x > y is false, that is, if x is less than or equal to y.
Strictly speaking, the operands of the logical operators should be boolean expressions, but Python is not very strict. Any nonzero number is interpreted as ``true.''
>>> 17 and True True
This flexibility can be useful, but there are some subtleties to it that might be confusing. You might want to avoid it (unless you know what you are doing).
5.4 Conditional execution
In order to write useful programs, we almost always need the ability to check conditions and change the behavior of the program accordingly. Conditional statements give us this ability. The simplest form is the if statement:
if x > 0: print 'x is positive'
if statements have the same structure as function definitions: a header followed by an indented body. Statements like this are called compound statements.
There is no limit on the number of statements that can appear in the body, but there has to be at least one. Occasionally, it is useful to have a body with no statements (usually as a place keeper for code you haven't written yet). In that case, you can use the pass statement, which does nothing.
if x < 0: pass # need to handle negative values!
5.5 Alternative execution
A second form of the if statement is alternative execution, in which there are two possibilities and the condition determines which one gets executed. The syntax looks like this:
if x%2 == 0: print 'x is even' else: print 'x is odd'
If the remainder when x is divided by 2 is 0, then we know that x is even, and the program displays a message to that effect. If the condition is false, the second set of statements is executed. Since the condition must be true or false, exactly one of the alternatives will be executed. The alternatives are called branches, because they are branches in the flow of execution.
5.6 Chained conditionals
Sometimes there are more than two possibilities and we need more than two branches. One way to express a computation like that is a chained conditional:
if x < y: print 'x is less than y' elif x > y: print 'x is greater than y' else: print 'x and y are equal'
elif is an abbreviation of ``else if.'' Again, exactly one branch will be executed. There is no limit on the number of elif statements. If there is an else clause, it has to be at the end, but there doesn't have to be one.
if choice == 'a': draw_a() elif choice == 'b': draw_b() elif choice == 'c': draw_c()
Each condition is checked in order. If the first is false, the next is checked, and so on. If one of them is true, the corresponding branch executes, and the statement ends. Even if more than one condition is true, only the first true branch executes.
5.7 Nested conditionals
One conditional can also be nested within another. We could have written the trichotomy example like this:
if x == y: print 'x and y are equal' else: if x < y: print 'x is less than y' else: print 'x is greater than y'
The outer conditional contains two branches. The first branch contains a simple statement. The second branch contains another if statement, which has two branches of its own. Those two branches are both simple statements, although they could have been conditional statements as well.
Although the indentation of the statements makes the structure apparent, nested conditionals become difficult to read very quickly. In general, it is a good idea to avoid them when you can.
Logical operators often provide a way to simplify nested conditional statements. For example, we can rewrite the following code using a single conditional:
if 0 < x: if x < 10: print 'x is a positive single-digit number.'
The print statement is executed only if we make it past both conditionals, so we can get the same effect with the and operator:
if 0 < x and x < 10: print 'x is a positive single-digit number.'
It is legal for one function to call another; it is also legal for a function to call itself. It may not be obvious why that is a good thing, but it turns out to be one of the most magical things a program can do. For example, look at the following function:
def countdown(n): if n <= 0: print 'Blastoff!' else: print n countdown(n-1)
If n is 0 or negative, it outputs the word, ``Blastoff!'' Otherwise, it outputs n and then calls a function named countdown---itself---passing n-1 as an argument.
What happens if we call this function like this?
The execution of countdown begins with n=3, and since n is greater than 0, it outputs the value 3, and then calls itself...
The execution of countdown begins with n=2, and since n is greater than 0, it outputs the value 2, and then calls itself...The execution of countdown begins with n=1, and since n is greater than 0, it outputs the value 1, and then calls itself...The execution of countdown begins with n=0, and since n is not greater than 0, it outputs the word, ``Blastoff!'' and then returns.
The countdown that got n=3 returns.
And then you're back in
3 2 1 Blastoff!
As another example, we can write a function that prints a string n times.
def print_n(s, n): if n <= 0: return print s print_n(s, n-1)
The rest of the function is similar to countdown: if n is greater than 0, it displays s and then calls itself to display s $n-1$ additional times. So the number of lines of output is 1 + (n - 1), which adds up to n.
For simple examples like this, it is probably easier to use a for loop. But we will see examples later that are hard to write with a for loop and easy to write with recursion, so it is good to start early.
5.9 Stack diagrams for recursive functions
In Section ??, we used a stack diagram to represent the state of a program during a function call. The same kind of diagram can help interpret a recursive function.
Every time a function gets called, Python creates a new function frame, which contains the function's local variables and parameters. For a recursive function, there might be more than one frame on the stack at the same time.
Figure ?? shows a stack diagram for countdown called with n = 3.
The four countdown frames have different values for the parameter n. The bottom of the stack, where n=0, is called the base case. It does not make a recursive call, so there are no more frames.
Exercise 1 Draw a stack diagram for
Exercise 2 Write a function called
5.10 Infinite recursion
If a recursion never reaches a base case, it goes on making recursive calls forever, and the program never terminates. This is known as infinite recursion, and it is generally not a good idea. Here is a minimal program with an infinite recursion:
def recurse(): recurse()
File "<stdin>", line 2, in recurse File "<stdin>", line 2, in recurse File "<stdin>", line 2, in recurse . . . File "<stdin>", line 2, in recurse RuntimeError: Maximum recursion depth exceeded
This traceback is a little bigger than the one we saw in the previous chapter. When the error occurs, there are 1000 recurse frames on the stack!
5.11 Keyboard input
The programs we have written so far are a bit rude in the sense that they accept no input from the user. They just do the same thing every time.
Python 2 provides a built-in function called
>>> text = raw_input() What are you waiting for? >>> print text What are you waiting for?
>>> name = raw_input('What...is your name?\n') What...is your name? Arthur, King of the Britons! >>> print name Arthur, King of the Britons!
If you expect the user to type an integer, you can try to convert the return value to int:
>>> prompt = 'What...is the airspeed velocity of an unladen swallow?\n' >>> speed = raw_input(prompt) What...is the airspeed velocity of an unladen swallow? 17 >>> int(speed) 17
But if the user types something other than a string of digits, you get an error:
>>> speed = raw_input(prompt) What...is the airspeed velocity of an unladen swallow? What do you mean, an African or a European swallow? >>> int(speed) ValueError: invalid literal for int()
The traceback Python displays when an error occurs contains a lot of information, but it can be overwhelming, especially when there are many frames on the stack. The most useful parts are usually:
>>> x = 5 >>> y = 6 File "<stdin>", line 1 y = 6 ^ SyntaxError: invalid syntax
In this example, the problem is that the second line is indented by one space. But the error message points to y, which is misleading. In general, error messages indicate where the problem was discovered, but the actual error might be earlier in the code, sometimes on a previous line.
The same is true of runtime errors.
Suppose you are trying to compute a signal-to-noise ratio in decibels. The formula is $SNR_db = 10 log10 (P_signal / P_noise)$. In Python, you might write something like this:
import math signal_power = 9 noise_power = 10 ratio = signal_power / noise_power decibels = 10 * math.log10(ratio) print decibels
Traceback (most recent call last): File "snr.py", line 5, in ? decibels = 10 * math.log10(ratio) OverflowError: math range error
The error message indicates line 5, but there is nothing wrong with that line. To find the real error, it might be useful to print the value of ratio, which turns out to be 0. The problem is in line 4, because dividing two integers does floor division. The solution is to represent signal power and noise power with floating-point values.
In general, error messages tell you where the problem was discovered, but that is often not where it was caused.
In Python 3, this example does not cause an error; the division operator performs floating-point division even with integer operands.
Fermat's Last Theorem says that there are no integers $a$, $b$, and $c$ such that
$$a^n + b^n = c^n $$ for any values of $n$ greater than 2.
If you are given three sticks, you may or may not be able to arrange them in a triangle. For example, if one of the sticks is 12 inches long and the other two are one inch long, it is clear that you will not be able to get the short sticks to meet in the middle. For any three lengths, there is a simple test to see if it is possible to form a triangle:
If any of the three lengths is greater than the sum of the other two, then you cannot form a triangle. Otherwise, you can. (If the sum of two lengths equals the third, they form what is called a ``degenerate'' triangle.)
The following exercises use TurtleWorld from Chapter ??:
Read the following function and see if you can figure out what it does. Then run it (see the examples in Chapter ??).
def draw(t, length, n): if n == 0: return angle = 50 fd(t, length*n) lt(t, angle) draw(t, length, n-1) rt(t, 2*angle) draw(t, length, n-1) lt(t, angle) bk(t, length*n)
The Koch curve is a fractal that looks something like Figure ??. To draw a Koch curve with length $x$, all you have to do is
The exception is if $x$ is less than 3: in that case, you can just draw a straight line with length $x$.
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