Chapter 8 Strings
8.1 A string is a sequence
>>> fruit = 'banana' >>> letter = fruit
The expression in brackets is called an index. The index indicates which character in the sequence you want (hence the name).
But you might not get what you expect:
>>> print letter a
For most people, the first letter of
>>> letter = fruit >>> print letter b
>>> letter = fruit[1.5] TypeError: string indices must be integers
len is a built-in function that returns the number of characters in a string:
>>> fruit = 'banana' >>> len(fruit) 6
>>> length = len(fruit) >>> last = fruit[length] IndexError: string index out of range
The reason for the IndexError is that there is no letter in ’banana’ with the index 6. Since we started counting at zero, the six letters are numbered 0 to 5. To get the last character, you have to subtract 1 from length:
>>> last = fruit[length-1] >>> print last a
8.3 Traversal with a for loop
A lot of computations involve processing a string one character at a time. Often they start at the beginning, select each character in turn, do something to it, and continue until the end. This pattern of processing is called a traversal. One way to write a traversal is with a while loop:
index = 0 while index < len(fruit): letter = fruit[index] print letter index = index + 1
This loop traverses the string and displays each letter on a line by itself. The loop condition is index < len(fruit), so when index is equal to the length of the string, the condition is false, and the body of the loop is not executed. The last character accessed is the one with the index len(fruit)-1, which is the last character in the string.
Write a function that takes a string as an argument and displays the letters backward, one per line.
Another way to write a traversal is with a for loop:
for char in fruit: print char
The following example shows how to use concatenation (string addition) and a for loop to generate an abecedarian series (that is, in alphabetical order). In Robert McCloskey’s book Make Way for Ducklings, the names of the ducklings are Jack, Kack, Lack, Mack, Nack, Ouack, Pack, and Quack. This loop outputs these names in order:
prefixes = 'JKLMNOPQ' suffix = 'ack' for letter in prefixes: print letter + suffix
The output is:
Jack Kack Lack Mack Nack Oack Pack Qack
Of course, that’s not quite right because “Ouack” and “Quack” are misspelled.
Modify the program to fix this error.
8.4 String slices
A segment of a string is called a slice. Selecting a slice is similar to selecting a character:
>>> s = 'Monty Python' >>> print s[0:5] Monty >>> print s[6:12] Python
The operator [n:m] returns the part of the string from the “n-eth” character to the “m-eth” character, including the first but excluding the last. This behavior is counterintuitive, but it might help to imagine the indices pointing between the characters, as in Figure 8.1.
If you omit the first index (before the colon), the slice starts at the beginning of the string. If you omit the second index, the slice goes to the end of the string:
>>> fruit = 'banana' >>> fruit[:3] 'ban' >>> fruit[3:] 'ana'
>>> fruit = 'banana' >>> fruit[3:3] ''
An empty string contains no characters and has length 0, but other than that, it is the same as any other string.
8.5 Strings are immutable
>>> greeting = 'Hello, world!' >>> greeting = 'J' TypeError: object does not support item assignment
The “object” in this case is the string and the “item” is the character you tried to assign. For now, an object is the same thing as a value, but we will refine that definition later. An item is one of the values in a sequence.
The reason for the error is that strings are immutable, which means you can’t change an existing string. The best you can do is create a new string that is a variation on the original:
>>> greeting = 'Hello, world!' >>> new_greeting = 'J' + greeting[1:] >>> print new_greeting Jello, world!
def find(word, letter): index = 0 while index < len(word): if word[index] == letter: return index index = index + 1 return -1
In a sense, find is the opposite of the  operator. Instead of taking an index and extracting the corresponding character, it takes a character and finds the index where that character appears. If the character is not found, the function returns -1.
This is the first example we have seen of a return statement inside a loop. If word[index] == letter, the function breaks out of the loop and returns immediately.
If the character doesn’t appear in the string, the program exits the loop normally and returns -1.
Modify find so that it has a third parameter, the index in word where it should start looking.
8.7 Looping and counting
The following program counts the number of times the letter a appears in a string:
word = 'banana' count = 0 for letter in word: if letter == 'a': count = count + 1 print count
This program demonstrates another pattern of computation called a counter. The variable count is initialized to 0 and then incremented each time an a is found. When the loop exits, count contains the result—the total number of a’s.
Encapsulate this code in a function named count, and generalize it so that it accepts the string and the letter as arguments.
Rewrite this function so that instead of traversing the string, it uses the three-parameter version of find from the previous section.
8.8 String methods
>>> word = 'banana' >>> new_word = word.upper() >>> print new_word BANANA
As it turns out, there is a string method named find that is remarkably similar to the function we wrote:
>>> word = 'banana' >>> index = word.find('a') >>> print index 1
In this example, we invoke find on word and pass the letter we are looking for as a parameter.
Actually, the find method is more general than our function; it can find substrings, not just characters:
>>> word.find('na') 2
>>> word.find('na', 3) 4
And as a third argument the index where it should stop:
>>> name = 'bob' >>> name.find('b', 1, 2) -1
This search fails because b does not appear in the index range from 1 to 2 (not including 2).
There is a string method called count that is similar
to the function in the previous exercise. Read the documentation
of this method
and write an invocation that counts the number of as
Read the documentation of the string methods at http://docs.python.org/2/library/stdtypes.html#string-methods. You might want to experiment with some of them to make sure you understand how they work. strip and replace are particularly useful.
The documentation uses a syntax that might be confusing.
For example, in
8.9 The in operator
The word in is a boolean operator that takes two strings and returns True if the first appears as a substring in the second:
>>> 'a' in 'banana' True >>> 'seed' in 'banana' False
For example, the following function prints all the letters from word1 that also appear in word2:
def in_both(word1, word2): for letter in word1: if letter in word2: print letter
With well-chosen variable names, Python sometimes reads like English. You could read this loop, “for (each) letter in (the first) word, if (the) letter (appears) in (the second) word, print (the) letter.”
Here’s what you get if you compare apples and oranges:
>>> in_both('apples', 'oranges') a e s
8.10 String comparison
The relational operators work on strings. To see if two strings are equal:
if word == 'banana': print 'All right, bananas.'
Other relational operations are useful for putting words in alphabetical order:
if word < 'banana': print 'Your word,' + word + ', comes before banana.' elif word > 'banana': print 'Your word,' + word + ', comes after banana.' else: print 'All right, bananas.'
Python does not handle uppercase and lowercase letters the same way that people do. All the uppercase letters come before all the lowercase letters, so:
Your word, Pineapple, comes before banana.
A common way to address this problem is to convert strings to a standard format, such as all lowercase, before performing the comparison. Keep that in mind in case you have to defend yourself against a man armed with a Pineapple.
When you use indices to traverse the values in a sequence, it is tricky to get the beginning and end of the traversal right. Here is a function that is supposed to compare two words and return True if one of the words is the reverse of the other, but it contains two errors:
def is_reverse(word1, word2): if len(word1) != len(word2): return False i = 0 j = len(word2) while j > 0: if word1[i] != word2[j]: return False i = i+1 j = j-1 return True
The first if statement checks whether the words are the same length. If not, we can return False immediately and then, for the rest of the function, we can assume that the words are the same length. This is an example of the guardian pattern in Section 6.8.
i and j are indices: i traverses word1 forward while j traverses word2 backward. If we find two letters that don’t match, we can return False immediately. If we get through the whole loop and all the letters match, we return True.
>>> is_reverse('pots', 'stop') ... File "reverse.py", line 15, in is_reverse if word1[i] != word2[j]: IndexError: string index out of range
For debugging this kind of error, my first move is to print the values of the indices immediately before the line where the error appears.
while j > 0: print i, j # print here if word1[i] != word2[j]: return False i = i+1 j = j-1
Now when I run the program again, I get more information:
>>> is_reverse('pots', 'stop') 0 4 ... IndexError: string index out of range
If I fix that error and run the program again, I get:
>>> is_reverse('pots', 'stop') 0 3 1 2 2 1 True
This time we get the right answer, but it looks like the loop only ran
three times, which is suspicious. To get a better idea of what is
happening, it is useful to draw a state diagram. During the first
iteration, the frame for
I took a little license by arranging the variables in the frame and adding dotted lines to show that the values of i and j indicate characters in word1 and word2.
Starting with this diagram, execute the program on paper, changing the values of i and j during each iteration. Find and fix the second error in this function.
A string slice can take a third index that specifies the “step size;” that is, the number of spaces between successive characters. A step size of 2 means every other character; 3 means every third, etc.
>>> fruit = 'banana' >>> fruit[0:5:2] 'bnn'
Use this idiom to write a one-line version of
The following functions are all intended to check whether a string contains any lowercase letters, but at least some of them are wrong. For each function, describe what the function actually does (assuming that the parameter is a string).
def any_lowercase1(s): for c in s: if c.islower(): return True else: return False def any_lowercase2(s): for c in s: if 'c'.islower(): return 'True' else: return 'False' def any_lowercase3(s): for c in s: flag = c.islower() return flag def any_lowercase4(s): flag = False for c in s: flag = flag or c.islower() return flag def any_lowercase5(s): for c in s: if not c.islower(): return False return True
ROT13 is a weak form of encryption that involves “rotating” each letter in a word by 13 places. To rotate a letter means to shift it through the alphabet, wrapping around to the beginning if necessary, so ’A’ shifted by 3 is ’D’ and ’Z’ shifted by 1 is ’A’.
Write a function called
For example, “cheer” rotated by 7 is “jolly” and “melon” rotated by -10 is “cubed”.
You might want to use the built-in functions ord, which converts a character to a numeric code, and chr, which converts numeric codes to characters.
Potentially offensive jokes on the Internet are sometimes encoded in ROT13. If you are not easily offended, find and decode some of them. Solution: http://thinkpython.com/code/rotate.py.
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